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3p^2-6p-7p=2
We move all terms to the left:
3p^2-6p-7p-(2)=0
We add all the numbers together, and all the variables
3p^2-13p-2=0
a = 3; b = -13; c = -2;
Δ = b2-4ac
Δ = -132-4·3·(-2)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{193}}{2*3}=\frac{13-\sqrt{193}}{6} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{193}}{2*3}=\frac{13+\sqrt{193}}{6} $
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